(x^2+4x+5)=0

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Solution for (x^2+4x+5)=0 equation:


Simplifying
(x2 + 4x + 5) = 0

Reorder the terms:
(5 + 4x + x2) = 0

Remove parenthesis around (5 + 4x + x2)
5 + 4x + x2 = 0

Solving
5 + 4x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + 4x + -5 + x2 = 0 + -5

Reorder the terms:
5 + -5 + 4x + x2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 4x + x2 = 0 + -5
4x + x2 = 0 + -5

Combine like terms: 0 + -5 = -5
4x + x2 = -5

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -5 + 4

Reorder the terms:
4 + 4x + x2 = -5 + 4

Combine like terms: -5 + 4 = -1
4 + 4x + x2 = -1

Factor a perfect square on the left side:
(x + 2)(x + 2) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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